Question

A 0.09 g honeybee acquires a charge of +23 pc while flying. The earth's electric field near the surface is typically (100 N/C, downward). What is the ratio of the electric force on the bee to the bee's weight? Multiply your answer by 10 before entering it below.

Answer 1

Step-by-step explanation:

Charge on honeybee q = 23 x 10⁻¹²

Force due to electric field E = E x q

= 100 x 23 x 10⁻¹²

= 23 x 10⁻¹⁰ N

Gravitational force on the honeybee

= m g = .09x 10⁻³ x 9.8

= .882x 10⁻³ N

Ratio of electric field and gravitational field

23 x 10⁻¹⁰ / .882x 10⁻³

26.07 x 10⁻⁷

= 26.07