Question

Your throw a ball straight upward at an initial speed of 5 m/s. How many times does the ball pass a point 2 m above the point you launched it from? Draw an x-t and a v-t diagram for the motion of this ball.

Answer 1

The ball never passes 2m high, Hmax=1.27m

Step-by-step explanation:

we assume the ball doesn't bounce when it hits the ground.

We calculate the maximum height, Vf = 0.

`v_(o)^(2)=2gH_(max)\\H_(max)=v_(o)^(2)/(2g)=5^(2)/(2*9.81)=1.27m`

So, the ball never passes 2m high.

Kinematics equations:

`x(t)=v_(o)t-1/2*g*t^(2)\\v(t)=v_(o)-gt`

Find annexed the graphics of x(t) and v(t)