Question

A total charge of 4.70 is distributed on two metal spheres. When the spheres are 10 cm apart, they each feel a repulsive force of 4.7 x 10^11 N. How much charge is on the sphere and which has the lower amount of charge?

Answer 1

Answer:0.114 C

Step-by-step explanation:

Given

Total 4.7 C is distributed in two spheres

Let
`q_1` and
`q_2` be the charges such that

`q_1+q_2=4.7`

and Force between charge particles is given by

`F=(kq_1q_2)/(r^2)`

`4.7* 10^11=(9* 10^9* q_1\cdot q_2)/(0.1^2)`

`q_1\cdot q_2=0.522`

put the value of
`q_1`

`q_2\left ( 4.7-q_2\right )=0.522`

`q_2^2-4.7q_2+0.522=0`

`q_2=(4.7\pm √(4.7^2-4* 1* 0.522))/(2)`

`q_2=0.114 C`

thus
`q_1=4.586 C`