Question

The car has a constant deceleration of 4.20 m/s^2. If its initial velocity was 24.0 m/s, how long does it take to come to a stop? Answer in s

Answer 1

The time is 5.71 sec.

Step-by-step explanation:

Given that,

Acceleration
`a= -4.20 m/s^2`

Initial velocity = 24.0 m/s

We need to calculate the time

Using equation of motion

v = u+at[/tex]

Where, v = final velocity

u = inital velocity

t = time

a = acceleration

Put the value into the formula

`0 =24.0 +(-4.20)* t`

`t = (-24.0)/(-4.20)`

`t=5.71\ sec`

Hence, The time is 5.71 sec.