Question

A race car has a speed of 80 m/s when the driver releases a drag parachute. If the parachute causes a deceleration of 4m/s^2, how far will the car travel before it stops?

Answer 1

The car travels 800m

Step-by-step explanation:

We will need two formulas to solve this question:

`V_(f)=V_(0)+at\\X=V_(0)t+(at^(2))/(2)`

We can obtain the the time by using the final velocity formula and replacing with known values:

`V_(f)=V_(0)+at\\\\0(m)/(s)=80(m)/(s)-4(m)/(s^(2))t\\\\4(m)/(s^(2))t=80(m)/(s)\\t=20 s`

Since we know the time, the question will be answered by inputing all the variables needed in the distance formula:

`X=V_(0)t+(at^(2))/(2)\\\\X=80(m)/(s)(20s)-(4(20s)^(2))/(2)=800m`