Answer:
option C
Step-by-step explanation:
given,
force act on west = 20 lb
force act at 45° east of north = 80 lb
magnitude of force = ?
∑ F y = 80 cos 45⁰
F y = 56.57 lb
magnitude of forces in x- direction
∑ F x = -20 + 80 sin 45⁰
= 36.57 lb
net force
F =
![√(F_x^2+F_y^2)](https://img.qammunity.org/2020/formulas/physics/college/pns5aacmkb4pia9pzmd6e891efryx4di4v.png)
F =
![√(56.57^2+36.57^2)](https://img.qammunity.org/2020/formulas/physics/college/uqyksix2r5hks0xbprfrysmev9mfrkznl6.png)
F = 67.36 lb≅ 67 lb
hence, the correct answer is option C