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A thin soap bubble of index of refraction 1.33 is viewed with light of wavelength 550.0nm and appears very bright. Predict a possible value of the thickness of the soap bubble.

User Rendel
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1 Answer

6 votes

Answer:

Thickness = 103.38 nm

Step-by-step explanation:

Given that:

The refractive index of the thin soap bubble = 1.33

The wavelength of the light = 550 nm

The minimum thickness that produces a bright fringe can be calculated by using the formula shown below as:


Thickness=\frac {\lambda}{4* n}

Where, n is the refractive index of the thin soap bubble = 1.33


{\lambda} is the wavelength

So, thickness is:


Thickness=\frac {550\ nm}{4* 1.33}

Thickness = 103.38 nm

User Jnyanendra Sethi
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