Question

An ice cube of volume 15 cm^3 and density 917 kg/m^3 is placed in ethyl alcohol of density 811 kg/m^3. What is the buoyant force on the ice? Will it float?

Answer 1

the buoyant force acting on the ice cube is 0.119 N

Step-by-step explanation:

given,

volume of ice cube = 15 cm³ = 15 × 10⁻⁶ m³

density of ice cube = 917 kg/m³

density of ethyl alcohol = 811 kg/m³

buoyant force = ?

The density of ice is more than ethyl alcohol hence it will sink.

buoyant force acting on the ice cube = ρ V g

= 811 × 15 × 10⁻⁶ × 9.81

=0.119 N

so, the buoyant force acting on the ice cube is 0.119 N