Answer:
C 2sp³ + 2sp³ O
Step-by-step explanation:
Carbon has an atomic number equal to 6, so its electronic distribution is:
1s²2s²2p²
Oxygen has an atomic number equal to 8, so its electronic distribution is:
1s²2s²2p⁴
In dimethyl ether, the bonds between carbon and hydrogen and carbon and oxygen are saturated, so there will be only sigma bonds. The sigma bonds occurs in hybrids orbitals, and pi bonds on normal orbitals. So, the carbons and the oxygen of that compound has hybridization
2sp³, because they need 4 hybrid orbitals.
So the bond C-O occurs between C 2sp³ + 2sp³ O