Question

Using local acceleration of gravity data from the Internet, de- termine the weight, in N, of a person whose mass is 80 kg living in: a. Mexico City, Mexico b. Cape Town, South Africa c. Tokyo, Japan d. Chicago, IL e. Copenhagen, Denmark

Answer 1

mass of a person is 80 kg

to calculate weight of the person = ?

a) Mexico City, Mexico

acceleration due to gravity in mexico = 9.779 m/s²

weight = 80× 9.779 = 782.32 N

b) Cape Town, South Africa

acceleration due to gravity in cape town = 9.796 m/s²

weight = 80× 9.796 = 783.68 N

c) Tokyo, Japan

acceleration due to gravity in Tokyo = 9.798 m/s²

weight = 80× 9.798 = 783.84 N

d) Chicago, IL

acceleration due to gravity in Chicago = 9.80 m/s²

weight = 80× 9.80 = 784 N

e) Copenhagen, Denmark

acceleration due to gravity in Copenhagen = 9.81 m/s²

weight = 80× 9.81 = 784.8 N

Answer 2

• Mexico Citi: 782.32 N
• Cape Town: 783.68 N
• Tokyo: 783.84 N
• Chicago: 784.24 N
• Copenhagen: 785.2 N

Step-by-step explanation:

The weight w its:

`w \ = \ m \ a`

where m is the mass and a is the acceleration.

Mexico City, Mexico

Local acceleration of gravity =
`9.779 (m)/(s^2)`

weight :

`w = \ 80\ kg \ * \ 9.779 (m)/(s^2)`

`w = \ 782.32 \ N`

Cape Town, South Africa

Local acceleration of gravity =
`9.796 (m)/(s^2)`

weight :

`w = \ 80\ kg \ * \ 9.796 (m)/(s^2)`

`w = \ 783.68 \ N`

Tokyo, Japan

Local acceleration of gravity =
`9.798 (m)/(s^2)`

weight :

`w = \ 80\ kg \ * \ 9.798 (m)/(s^2)`

`w = \ 783.84 \ N`

Chicago, IL

Local acceleration of gravity =
`9.803 (m)/(s^2)`

weight :

`w = \ 80\ kg \ * \ 9.803 (m)/(s^2)`

`w = \ 784.24 \ N`

Copenhagen, Denmark

Local acceleration of gravity =
`9.815 (m)/(s^2)`

weight :

`w = \ 80\ kg \ * \ 9.815 (m)/(s^2)`

`w = \ 785.2 \ N`