Question

A mechanics shop has a 16,500 N car sitting on a large car lift of 125 cm^2 piston. How much force is needed to be applied to the small piston of area 4.51 cm^2 to lift it?

Answer 1

Answer:595.32 N

Step-by-step explanation:

Given

Mechanic shop has a car of weight(
`F_1`) 16,500 N

Area of lift(
`A_1`)=
`125 cm^2`

Area of small piston(
`A_2`)=
`4.51 cm^2`

According to pascal's law pressure transmit will be same in all direction in a closed container

`P_1=P_2`

`(F_1)/(A_1)=(F_2)/(A_2)`

`F_2=F_1(A_2)/(A_1)`

`F_2=16,500* (4.51)/(125)=595.32 N`