Question

A 0.50 Kg billard ball moving at 1.5 m/s strikes a second 0.50 kg billiard ball which is at rest on the table.If the first ball slows down to a speed of 0.10 m/s, then what is the speed of the second ball ? Please explain.

Answer 1

velocity of second billiard after collision = 1.4 m/sec

Step-by-step explanation:

We have mass of billiard let
`m_1=0.5kg`

Velocity of billiard let
`v_1=1.5m/sec`

Mass of second second billiard let
`m_2=0.5kg`

Velocity of second billiard before collision 0 m/sec billiard

Velocity of first billiard after collision 0.1 m/sec

Now according conservation of momentum

Momentum before collision and after collision will be same

So momentum before collision = momentum after collision

`0.5* 1.5+0.5* 0=0.5* 0.1+0.5* velovity\ of\ second\ biliard\ after\ collision`

So velocity of second billiard after collision = 1.4 m/sec