Answer:
Average speed 21.67 m/s
Average velocity=8.33 m/s
Step-by-step explanation:
In order to solve this, We have to know the difference between speed and velocity.
Velocity is a vector value, so it means we have to specify the magnitud and direction, we take the displacement instead of the distance.
speed is an scalar value, we only care about the magnitud, we take in count the total distance.
first we have to get the total amount of time
Total time= 30min+10min+20min=60min
Total time is= 3600 seconds
the distance on the first trame is:
![X1=v*t\\\\X1=30m/s*(30min)(60sec/1min)\\X1=54km](https://img.qammunity.org/2020/formulas/physics/college/jqnbiykv652cqifffs5xot013tpspelh52.png)
the distance on the second trame is:
![X2=v*t\\\\X2=20m/s*(20min)(60sec/1min)\\X2=24km](https://img.qammunity.org/2020/formulas/physics/college/h50n5hsghl5kiuk7b8p0ke4hu3a8uwdakn.png)
The total distance is the sum of both values
Td=78km
the Displacement is the vectorial sum of them, because the second trame is opposite the first, we have to substract the second distance
D=54-24=30km
![Speed(avg)=(distance)/(time) \\\\Speed(avg)=(78000m)/(3600) \\\\Speed(avg)=21.67 m/s](https://img.qammunity.org/2020/formulas/physics/college/dc8nvxeb86jxr04985a755aelmf0ftzavz.png)
![Velocity(avg)=(displacement)/(time) \\\\Velocity(avg)=(30000m)/(3600) \\\\Velocity(avg)=8.33 m/s](https://img.qammunity.org/2020/formulas/physics/college/26sfqfqxjnkw7tla92twfwi4n9ukqr3wgz.png)