Question

A moving curling stone, A, collides head on with stationary stone, B. Stone B has a larger mass than stone A. If friction is negligible during this linear elastic collision, a)stone A will slow down but continue moving forward b) stone A will rebound and stone B will move forward c) stone a will rebound but stone b will remain stationary d) stone A will stop and stone b will move forward

Answer 1

The correct answer is option 'c': Smaller stone rebounds while as larger stone remains stationary.

Step-by-step explanation:

Let the velocity and the mass of the smaller stone be 'm' and 'v' respectively

and the mass of big rock be 'M'

Initial momentum of the system equals

`p_i=mv+0=mv`

Now let after the collision the small stone move with a velocity v' and the big roch move with a velocity V'

Thus the final momentum of the system is

`p_f=mv'+MV'`

Equating initial and the final momenta we get

`mv=mv'+MV'\\\\m(v-v')=MV'.....i`

Now since the surface is frictionless thus the energy is also conserved thus

`E_i=(1)/(2)mv^2`

Similarly the final energy becomes

`E_f=(1)/(2)mv'^2+(1)/(2)MV'^2`\

Equating initial and final energies we get

`(1)/(2)mv^2=(1)/(2)mv'^2+(1)/(2)MV'^2\\\\mv^2=mv'^2+MV'^2\\\\m(v^2-v'^2)=MV'^2\\\\m(v-v')(v+v')=MV'^2......(ii)`

Solving i and ii we get

`v+v'=V'`

Using this in equation i we get

`v'=(v(m-M))/((M-m))=-v`

Thus putting v = -v' in equation i we get V' = 0

This implies Smaller stone rebounds while as larger stone remains stationary.