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What voltage must be applied to an 6 nF capacitor to store 0.14 mC of charge? Give answer in terms of kV.
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What voltage must be applied to an 6 nF capacitor to store 0.14 mC of charge? Give answer in terms of kV.

User Adrian Walls
by
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1 Answer

4 votes

Answer:


V=23.3kV

Step-by-step explanation:

Definition of the capacitance C, where a voltage V is applied and a charge Q is stored:


Q=C*V

We solve to find V:


V=Q/C=0.14*10^(-3)C/6*10^(-9)F)=2.33*10^(4)V=23.3kV

User Robert Munteanu
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4.3k points
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