Question

At what partial pressure are argon atoms expected to have a free travel of approximately 5 µm, if the gas is at a temperature of 400 K? The cross section of collision, σ, or Argon is 0.28 nm2

Ar molar mass is 39.9 g/mole

Answer 1

2790 Pa

Step-by-step explanation:

Given wavelength λ= 5μm

temperature T= 400 K

cross section of collision σ= 0.28 nm^2

molar mass = 39.9 g/mole

pressure =
`P= (RT)/(√(2)N_A\sigma\lambda )`

putting values we get

=
`(8.314*400)/(√(2)*6.022*10^(23)*0.28*10^(-18)*5*10^(-6) )`

⇒P = 2790 J/m^3

the partial pressure are argon atoms expected= 2790 Pa