Question

What is the strength of the electric field between two parallel conducting plates separated by 6 cm and having a potential difference (voltage) between them of 4.18 ×10^4 V ? Give answer in terms of 10^6 V/m.

Answer 1

`E=0.697*10^(6)V/m\\`

Step-by-step explanation:

If the voltage is constant, the relation between the electric field E and the voltage V , for two plates separated by a distance d, is:

`V=E*d\\`

d=6cm=0.06m

V=4.18×10^4 V

We solve to find E:

`E=V/d=4.18*10^(4)/0.06=6.97*10^(5)=0.697*10^(6)V/m\\`