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A reaction at -6.0 °C evolves 786. mmol of sulfur tetrafluoride gas. Calculate the volume of sulfur tetrafluoride gas that is collected. You can assume the pressure in the room is exactly 1 atm. Be sure your answer has the correct number of significant digits. volume: 1 X I

User WetFish
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Answer:

V of Sulfur tetrafluoride is 17.2 L

Step-by-step explanation:

Given data;

T = -6°C = 267K [1° C = 273 K]

n = 786 mmol of SF4 which is 0.786 mol

P = 1 atm

from ideal gas law we have

PV = nRT

where n is mole, R is gas constant, V is volume


V = (nRT)/(P)
V = (0.786 mol * 0.082 atmL/mol K ** 267K)/(1atm) = 17.2 L

V of Sulfur tetrafluoride is 17.2 L

User IlSavo
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