Answer:
The function is injective.
The function is surjective.
The function is bijective.
Step-by-step explanation:
A function f(x) is injective if, and only if, a = b when f(a) = f(b).
So:
![f(x) = -3x + 4](https://img.qammunity.org/2020/formulas/computers-and-technology/college/w3zjief7pws0lxgyl0sdb26io1xokrh9na.png)
![f(a) = f(b)](https://img.qammunity.org/2020/formulas/computers-and-technology/college/oiukrr18awe8tqqxnnmqpm7tdnyat7tvvb.png)
![-3a + 4 = -3b + 4](https://img.qammunity.org/2020/formulas/computers-and-technology/college/99osa5mf8q5itet1daxccvqonlxelfp2ky.png)
*(-1)
![3a = 3b](https://img.qammunity.org/2020/formulas/computers-and-technology/college/jj60hst667oe8spfs69741r6m2yqsl5fwu.png)
![a = (3b)/(3)](https://img.qammunity.org/2020/formulas/computers-and-technology/college/uv7lvlpk36uffxd55wkx5ps13h059zcg4k.png)
![a = b](https://img.qammunity.org/2020/formulas/mathematics/high-school/c593flst1g6l3nwrv6z5lck7f0je2tiicp.png)
Since
if, and only if,
, the function is injective.
A function f(x) is surjective, if, and only if, for each value of y, there is a value of x such that f(x) = y.
Here we have:
![f(x) = y](https://img.qammunity.org/2020/formulas/computers-and-technology/college/b1pdjgsyzide5fe37ceotbfu27vvaadd4q.png)
![y = -3x + 4](https://img.qammunity.org/2020/formulas/computers-and-technology/college/i74uwwu5bpnj3osebjc706pfe0de8q7e7w.png)
![3x = 4-y](https://img.qammunity.org/2020/formulas/computers-and-technology/college/qxhjb4zjasomdi9d5wilylejbipvc3s97t.png)
![x = (4 - y)/(3)](https://img.qammunity.org/2020/formulas/computers-and-technology/college/siab5ofnfh1c4ey71nlpd9tni9jlzuoarv.png)
The domain of x is the real numbers, which means that for each value of y, there is a value of x such that
. So, the function is surjective.
A function f(x) is bijective when it is both injective and surjective. So this function is bijective.