Answer:
voltage across capacitor
![V_C=i* X_C=0.022* 0.04=9* 10^(-4)V](https://img.qammunity.org/2020/formulas/physics/college/gxhkx8ft7hbstmym733u2wyu6wbwy8x5oz.png)
Voltage across resistor
Step-by-step explanation:
We have given resistance R = 2000 OHM
Capacitance
![C=1000\mu F=0.001F](https://img.qammunity.org/2020/formulas/physics/college/ywfa9vy73yto07wffmu35bzt8k2u6qtost.png)
Voltage V = 45 volt
Frequency = 4000 Hz
Capacitive reactance
![X_C=(1)/(\omega C)=(1)/(2* \pi * 4000* 0.001)=0.04ohm](https://img.qammunity.org/2020/formulas/physics/college/zmrp8xnicge96wtasy1ggnzec467uc2tfx.png)
Impedance
![Z=√(R^2+X_C^2)=√(2000^2+0.04^2)=2000ohm](https://img.qammunity.org/2020/formulas/physics/college/n1r9b641sajn87etz2cnmftraihmoei76n.png)
Current
![i=(V)/(Z)=(45)/(2000)=0.022A](https://img.qammunity.org/2020/formulas/physics/college/igaq1yucjvy1nalkl9hk0v331i12u5j0vj.png)
Now voltage across capacitor
![V_C=i* X_C=0.022* 0.04=9* 10^(-4)V](https://img.qammunity.org/2020/formulas/physics/college/gxhkx8ft7hbstmym733u2wyu6wbwy8x5oz.png)
Voltage across resistor