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You have put a 1,000 μF capacitor and a 2,000 ohm resistor in series with an AC voltage source with amplitude of 45 V and frequency of 4,000 Hz. What is Vout across the capacitor? What is Vout across the resistor?

User Gentry
by
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1 Answer

1 vote

Answer:

voltage across capacitor
V_C=i* X_C=0.022* 0.04=9* 10^(-4)V

Voltage across resistor
V_R=i* R=0.022* 2000=80V

Step-by-step explanation:

We have given resistance R = 2000 OHM

Capacitance
C=1000\mu F=0.001F

Voltage V = 45 volt

Frequency = 4000 Hz

Capacitive reactance
X_C=(1)/(\omega C)=(1)/(2* \pi * 4000* 0.001)=0.04ohm

Impedance
Z=√(R^2+X_C^2)=√(2000^2+0.04^2)=2000ohm

Current
i=(V)/(Z)=(45)/(2000)=0.022A

Now voltage across capacitor
V_C=i* X_C=0.022* 0.04=9* 10^(-4)V

Voltage across resistor
V_R=i* R=0.022* 2000=80V

User Sandeepan Nath
by
5.0k points