Answer:
absolute pressure = 1.07 lbft/in^2
Step-by-step explanation:
given data:
vaccum gauge reading h = 27.86 inch = 2.32 ft
we know that
gauge pressure p is given as
![p = \rho gh](https://img.qammunity.org/2020/formulas/physics/college/hp73dejth32231qpruccox3oespevh5c7a.png)
![p = 848 \ lb/ft^3 * 32 \ ft/s^2 *2.32 ft = 62955.52 \ lbft/s^2 * 1/ft^2](https://img.qammunity.org/2020/formulas/physics/college/fwvxrjp7yhcjprvhi12eqh4zwyu7b7ti72.png)
we know that
![1\ lb ft\s^2 = (1)/(32.174)\ lbft](https://img.qammunity.org/2020/formulas/physics/college/lm29s8dccv8s1fjr2klyvgjj2tzk8a7b3x.png)
1 ft = 12 inch
therefore
![p = 62955.52 * (1)/(32.174) * (1)/(12^2)\ lbf/in^2](https://img.qammunity.org/2020/formulas/physics/college/5vqw4in1jv6i3t0c8vmn25xiw73xixekyd.png)
![p = 13.59\ lbft/in^2](https://img.qammunity.org/2020/formulas/physics/college/vupo2meq633qyp7ymwll32b0y0hbhe0wyn.png)
![P_(atm) = 14.66\ lbf/in^2](https://img.qammunity.org/2020/formulas/physics/college/haf44nuvpg1x33kj7m9v2ndhpboixj4ukq.png)
so absolute pressure =
![P_(atm) - p](https://img.qammunity.org/2020/formulas/physics/college/thfhv4h7xgj7kuio97cpob1340uitys6gl.png)
= 14.66 - 13.59 = 1.07 lbft/in^2