Answer:
Final velocity v = 8.944 m/sec
Step-by-step explanation:
We have given distance S = 40 meters
Time t = 10 sec
As it starts from rest so initial velocity u = 0
From second equation of motion
![s=ut+(1)/(2)at^2](https://img.qammunity.org/2020/formulas/physics/middle-school/y4u77sotscfafpxzyglg8hbmefjo11knkz.png)
![40=0* 10+(1)/(2)a10^2](https://img.qammunity.org/2020/formulas/physics/college/7pj4xr5trkd2gotf96ij7ou5cc79e84hg5.png)
![a=0.8944m/sec^2](https://img.qammunity.org/2020/formulas/physics/college/j5rdpadc26o4efrbcuzlx3wdohlgl30y6h.png)
Now from first equation of motion
, here v is final velocity, u is initial velocity, a is acceleration and t is time
So
![v=u+at=0+0.8944* 10=8.944m/sec](https://img.qammunity.org/2020/formulas/physics/college/povqv07wif7wfm3fp6aprkjecyfy1cqzbb.png)