Question

Jacob is traveling at 5.00 m/s North. Jacob throws a ball with a velocity of 5.00 m/s South. Jacob throws the ball from a height of 1.45 m above the ground. Assuming gravitational acceleration is 9.81 m/s^2, how long does the ball stay in the air after it is thrown? Describe the motion of the ball relative to the ground. Describe the motion of the ball relative to Jacob.

Answer 1

Answer:t=0.54 s

Step-by-step explanation:

Given

Jacob is traveling 5 m/s in North direction

Jacob throw a ball with a in south direction with a velocity of 5 m/s

Ball is thrown in opposite direction of motion of car therefore it seems as if it is dropped from car as its net horizontal velocity is 5-5=0

Time taken by ball to reach ground

`s=ut+(gt^2)/(2)`

`1.45=0+(9.81* t^2)/(2)`

`t^2=frac{2* 1.45}{9.81}`

t=0.54 s

Motion of ball will be straight line