Question

Radon-219 decays to radon-218 by releasing... a. a positron b.a muon O c. a neutron O d. an electron O e. a proton

Answer 1

Answer: Option (c) is the correct answer.

Step-by-step explanation:

A positron is denoted as
`^(0)_(+1)e`, a neutron is denoted as
`^(1)_(0)n`, an electron is denoted as
`^(0)_(-1)e`, and a proton is denoted as
`^(1)_(1)p`.

Therefore, when
`^(219)Rn` will decay into
`^(218)Rn` this means there occurs decrease in its mass number. Hence, it means a neutron will be releasing during this reaction.

The reaction will be as follows.

`^(219)Rn \rightarrow ^(218)Rn + ^(1)_(0)n`