Question

A cube with sides of area 18 cm^2 contains a 6.0 nanoCoulomb charge. Find the flux of the electric field through the surface of the cube in unis of Nm^2/C. Enter a number with one digit behind the decimal point.

Answer 1

The flux of the electric field is 677.6 Nm²/C

Step-by-step explanation:

Given that,

Area = 18 cm²

Charge = 6.0 nC

We need to calculate the flux of the electric field

Using Gauss's law

`\phi=(q)/(\epsilon_(0))`

Where, q = charge

`\epsilon_(0)` =permittivity of free space

Put the value into the formula

`\phi=(6.0*10^(-9))/(8.854*10^(-12))`

`\phi=677.6\ Nm^2/C`

Hence, The flux of the electric field is 677.6 Nm²/C.