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A cube with sides of area 18 cm^2 contains a 6.0 nanoCoulomb charge. Find the flux of the electric field through the surface of the cube in unis of Nm^2/C. Enter a number with one digit behind the decimal point.

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Answer:

The flux of the electric field is 677.6 Nm²/C

Step-by-step explanation:

Given that,

Area = 18 cm²

Charge = 6.0 nC

We need to calculate the flux of the electric field

Using Gauss's law


\phi=(q)/(\epsilon_(0))

Where, q = charge


\epsilon_(0) =permittivity of free space

Put the value into the formula


\phi=(6.0*10^(-9))/(8.854*10^(-12))


\phi=677.6\ Nm^2/C

Hence, The flux of the electric field is 677.6 Nm²/C.

User Pavel Krymets
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