Question

According to the following reaction, how many grams of water are produced in the complete reaction of 29.7 grams of ammonia? 4 NH3(g) + 5 O2(g) + 4 NO(g) + 6 H2O(g) grams H2O

Answer 1

The complete reaction of 29.7 grams of NH3 would produce 47.099 grams of water by converting the given mass of NH3 to moles, using the balanced chemical equation to find the ratio of NH3 to H2O, and then converting the moles of H2O to grams.

Step-by-step explanation:

To find out how many grams of water are produced in the complete reaction of 29.7 grams of ammonia (NH3), we need to use stoichiometry, which involves several steps:

1. First, calculate the molar mass of NH3 which is 14.01 (for N) + 3×1.01 (for H) = 17.03 g/mol.
2. Next, convert the given mass of NH3 to moles by dividing by the molar mass: 29.7 g ÷ 17.03 g/mol = 1.743 mol of NH3.
3. Using the balanced chemical equation 4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(l), for every 4 mol of NH3, 6 mol of H2O are produced. This means for 1.743 mol NH3, we'd produce (1.743 mol NH3 × 6 mol H2O) ÷ 4 mol NH3 = 2.6145 mol H2O.
4. Finally, convert the moles of H2O to grams. The molar mass of H2O is 18.02 g/mol, so 2.6145 mol × 18.02 g/mol = 47.099 grams of H2O.

Therefore, the complete reaction of 29.7 grams of NH3 would produce 47.099 grams of water (H2O).

Answer 2

Answer: The mass of water produced in the reaction is 47.25 grams.

Step-by-step explanation:

To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}` .....(1)

Given mass of ammonia = 29.7 g

Molar mass of ammonia = 17 g/mol

Putting values in equation 1, we get:

`\text{Moles of ammonia}=(29.7g)/(17g/mol)=1.75mol`

The given chemical reaction follows:

`4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g)`

By stoichiometry of the reaction:

4 moles of ammonia produces 6 moles of water.

So, 1.75 moles of ammonia will produce =
`(6)/(4)* 1.75=2.625mol` of water.

Now, calculating the mass of water by using equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 2.625 moles

Putting values in equation 1, we get:

`2.625mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=47.25g`

Hence, the mass of water produced in the reaction is 47.25 grams.