Question

Look at the equation below. What is the acid on the left-hand side of the equation? H30 СНЗСОО" CH3COOH + H20 O a. CH3COOH ОБ.Н20 O c. None of the above.

Answer 1

c. None of the above

Step-by-step explanation:

The equation is:

H₃O⁺ + CH₃COO⁻ ⇒ CH₃COOH + H₂O

An acid is a species that donates a proton. Thus, the acid is the species on the reactants' side that has one proton more than it's conjugate base species on the products's side.

The available options are:

a. CH₃COOH

b. H₂O

c. None of the above.

Both CH₃COOH and H₂O are on the right-hand side of the equation, so the answer must be c. The answer to the problem is H₃O⁺, since it has lost a proton and become H₂O.