Question

A rocket fired two engines simultaneously. One produces a thrust 725 N directly forward while the other gives a 513N thrust at 32.4degrees above the forward direction. Find the magnitude and direction ( relative to the forward direction) of the resultant force that these engines exert on the rocket

Answer 1

Magnitude of resultant force is 1190.314 N

Direction of force is 13.352°

Step-by-step explanation:

given data:

thrust force = 725 N

Angle = 32.4 degree

Let x is consider as positive direction

Resultant force in x direction is

Rx = 725 + 513cos32.4 = 1158.14 N

and Resultant force perpendicular to x direction is:

Ry = 513sin32.4 = 274.88 N

Magnitude of resultant force is

`R=√(R_x^2+R_y^2) = 1190.314N`

and resultant force direction is

`\theta=tan^(-1)(R_y)/(R_x) = 13.352\degree`