Question

If the volame ofa gas coetainer at 32°C changes froem 1.55 L to 753 ml, what will the final temperature be? Assume the pressure doesn't change and the amount of gas in the coatainer doesn't change. Remember that there are 1,000 ml in 1 L. O a. 149°C Ob. 353 C Oc. 273C O d.-125 C Oe None of the above.

Answer 1

Answer : The final temperature of gas will be, 149 K

Explanation :

Charles' Law : It is defined as the volume of gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

`V\propto T`

or,

`(V_1)/(V_2)=(T_1)/(T_2)`

where,

`V_1` = initial volume of gas = 1.55 L

`V_2` = final volume of gas = 753 ml = 0.753 L

`T_1` = initial temperature of gas =
`32^oC=273+32=305K`

`T_2` = final temperature of gas = ?

Now put all the given values in the above formula, we get the final temperature of the gas.

`(1.55L)/(0.753L)=(305K)/(T_2)`

`T_2=149K`

Therefore, the final temperature of gas will be, 149 K