Question

You have a red ballooe that has a volume of 20 liters, a pressure of 1.5 atmospheres and a temperature of 28 C. What is the volume of the balloon if you change the pressure to 5 atmospheres and change the temperature to S0°C Oa.1.07 L Ob3.0 L 0.64 L O d.o.42 L

Answer 1

Step-by-step explanation:

The given data is as follows.

`P_(1)` = 1.5 atm,
`V_(1)` = 20 L,
`T_(1)` = (28 + 273) K = 301 K

`P_(2)` = 5 atm,
`V_(2)` = ?,
`T_(2)` = (50 + 273) K = 323 K

Formula to calculate the volume will be as follows.

`(P_(1) * V_(1))/(T_(1))` =
`(P_(2) * V_(2))/(T_(2))`

Putting the given values into the above formula as follows.

`(P_(1) * V_(1))/(T_(1))` =
`(P_(2) * V_(2))/(T_(2))`

`(1.5 atm * 20 L)/(301 K)` =
`(5 atm * V_(2))/(323 K)`

`V_(2)` = 0.64 L

Thus, we can conclude that the change in volume of the balloon will be 0.64 L.