Question

35S has a half-life of 88 days. You start with 128 micrograms of 3Ss. How much 35s is left after 264 days? O a. 32 micrograms b.8 micrograms O c. 64 micrograms O d. 16 micrograms O e. 4 micrograms

Answer 1

Option d, Amount left = 16 μg

Step-by-step explanation:

Half life = 88 days

Initial concentration = 128 μg

`No.\ of\ half\ life=(Total\ days)/(t_(1/2))`

`No.\ of\ half\ life=(264)/(88) = 3`

Amount of material left after n half life =
`(Amount\ of\ starting\ material)/(2^n)`

Where, n = No. of half life

Amount of material left =
`(128)/(2^3)`

=
`(128)/(8) = 16`μg

SO, option d is correct