53.4k views
3 votes
10,101 base 2 + 11,011 base 2 =

User Nicoleta
by
5.5k points

1 Answer

4 votes

Answer:

110,000 base 2

Explanation:

column 1 [the first position in the number]:

1+1=0, (carry 1)

column 2:

0+1 +1 (carried)=0, (carry 1)

column 3:

1+0+1 (carried)=0, (carry 1)

column 4:

0+1+1 (carried)=0, (carry 1)

column 5:

1+1+1=1, (carry 1)

then you write the last 1 'cause there is n number to add with:


10,101_(2)+11,011_(2)=110,000_(2)

In binary system the highest number to write is 1, if you add 1+1, it jumps to 0, and you have to carry 1 to the next position.

If you are not sure about the sum, you can convert the numbers in base 2, to base 10, so you can know if it is correct:


10,101_(2)=21_(10)\\11,011_(2)=27_(10)\\110,000_(2)=48_(10)

So 21+27=48.

In decimal system when you add 9+1, it jumps to 0 and then you have to carry 1 to the next position, because the the highest number you can write is 9.

User Mateusz Stefek
by
5.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.