Answer:
110,000 base 2
Explanation:
column 1 [the first position in the number]:
1+1=0, (carry 1)
column 2:
0+1 +1 (carried)=0, (carry 1)
column 3:
1+0+1 (carried)=0, (carry 1)
column 4:
0+1+1 (carried)=0, (carry 1)
column 5:
1+1+1=1, (carry 1)
then you write the last 1 'cause there is n number to add with:
![10,101_(2)+11,011_(2)=110,000_(2)](https://img.qammunity.org/2020/formulas/mathematics/college/26yawrpn0k1c48wsabo32ja2q3eatd3e8o.png)
In binary system the highest number to write is 1, if you add 1+1, it jumps to 0, and you have to carry 1 to the next position.
If you are not sure about the sum, you can convert the numbers in base 2, to base 10, so you can know if it is correct:
![10,101_(2)=21_(10)\\11,011_(2)=27_(10)\\110,000_(2)=48_(10)](https://img.qammunity.org/2020/formulas/mathematics/college/w0geiop7yh6nlfds903pr9tvd0snib10sn.png)
So 21+27=48.
In decimal system when you add 9+1, it jumps to 0 and then you have to carry 1 to the next position, because the the highest number you can write is 9.