Question

A circular hole in an aluminum plate is 2.739 cm in diameter at 0.000°C. What is the change in its diameter when the temperature of the plate is raised to 108.0°C? ________ cm

Answer 1

`L = 2.746 cm`

Step-by-step explanation:

As we know that thermal expansion coefficient of aluminium is given as

`\alpha = 24 * 10^(-6) per ^oC`

now we also know that after thermal expansion the final length is given as

`L = L_o(1 + \alpha \Delta T)`

here we know that

`L_o = 2.739 cm`

`\alpha = 24 * 10^(-6)`

`\Delta T = 108 - 0= 108^oC`

now we will have

`L = 2.739(1 + 24 * 10^(-6) (108))`

`L = 2.746 cm`