What plate area is required if an air-filled, parallel-plate capacitor with a plate separation of 3.1 mm is to have a capacitance of 23 pF ?

Question

asked Aug 1, 2020 21.2k views

1 Answer

Wahab · Answer 1 · 2020-08-07T10:36:13+0000

Step-by-step explanation:

Given that,

Separation between the plates, d = 3.1 mm = 0.0031 m

Capacitance of the capacitor, C = 23 pF

We need to find the area of the plate. The capacitance of a parallel plate capacitor is given by :

$C=(A\epsilon_0)/(d)$

$A=(Cd)/(\epsilon_0)$

A=(23* 10^(-12)* 0.0031)/(8.85* 10^(-12))

$A=0.0080\ m^2$

or

$A=80\ cm^2$

So, the area of the plate is 80 square centimetres. Hence, this is the required solution.