Question

A 75-m-long train begins uniform acceleration from rest. The front of the train has a speed of 18 m/swhen it passes a railway worker who is standing 125 m from where the front of the train started. What will be the speed of the last car as it passes the worker?

Answer 1

Answer:22.76 m/s

Step-by-step explanation:

Given

Train length(L)=75 m

Front of train after travelling 125 m is 18 m/s

Time taken by the front of train to cover 125 m

`v^2-u^2=2as`

`18^2-0=2* a* 125`

`a=1.296 m/s^2`

Speed of the last part of train when it passes the worker i.e. front of train has to travel has to travel a distance of 125+75=200 m

`v^2-u^2=2as`

`v^2=2* 1.296* 200`

`v=√(518.4)=22.76 m/s`