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A 7.80-nc charge is located 1.81 m from a 4.30-nc point charge. (a) Find the magnitude of the electrostatic force that one charge exerts on the other. N (b) Is the force attractive or repulsive? O attractive O repulsive

1 Answer

5 votes

Step-by-step explanation:

Given that,

Charge 1,
q_1=7.8\ nC=7.8* 10^(-9)\ C

Charge 2,
q_2=4.3\ nC=4.3* 10^(-9)\ C

Distance between charges, r = 1.81 m

(a) The electrostatic force that one charge exerts on the another is given by :


F=k(q_1q_2)/(r^2)


F=9* 10^9* (7.8* 10^(-9)* 4.3* 10^(-9))/((1.81)^2)


F=9.21* 10^(-8)\ N

(b) As both charges are positively charged. So, the force of attraction between them is repulsive.

User SilentGhost
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