Question

A busy chipmunk runs back and forth along a straight line of acorns that has been set out between his burrow and a nearby tree. At some instant the little creature moves with a velocity of -1.03 m/s. Then, 2.47 s later, it moves at the velocity 1.51 m/s. What is the chipmunk\'s average acceleration during the 2.47-s time interval?

Answer 1

a = 1.02834008 m/s2

Step-by-step explanation:

given data:

initial velocity u = -1.03 m/s

time t = 2.47 s later

final velocity v = 1.51 m/s

average acceleration is given as a

`a  = ((v - u))/(t)`

putting all value to get required value of acceleration:

`= ((1.51 -(- 1.03)))/(2.47)`

`= (1.51+1.03)/(2.47)`

= 1.02834008 m/s2