Question

A bird watcher meanders through the woods, walking 1.46 km due east, 0.123 km due south, and 4.24 km in a direction 52.4° north of west. The time required for this trip is 1.285 h. Determine the magnitudes of the bird watcher's (a)displacement and (b) average velocity.

Answer 1

(a). The displacement is 3.11 m.

(b). The average velocity is 2.42 km/hr.

Step-by-step explanation:

Given that,

A bird watcher meanders through the woods, walking 1.46 km due east, 0.123 km due south, and 4.24 km in a direction 52.4° north of west.

(a). We need to calculate the displacement

Using Pythagorean theorem

`D=√((OA)^2+(AB)^2)`

`D=√((1.46-4.24\sin52.4)^2+(0.123-4.24\cos52.4)^2)`

`D=3.11\ km`

(b). We need to calculate the average velocity

Using formula of average velocity

`v_(avg)=(D)/(T)`

Where, D = displacement

T = time

Put the value into the formula

`v_(avg)=(3.11)/(1.285)`

`v_(avg)=2.42\ km/hr`

Hence, (a). The displacement is 3.11 m.

(b). The average velocity is 2.42 km/hr.