Question

How many moles are in 250.0 mL of a 0.15 M nitric acid solution?

Answer 1

Step-by-step explanation:

It is given that molarity is 0.15 M and volume is 250.0 ml. As 1 ml equals 0.001 l.

Hence, 250.0 ml = 0.25 l.

Also, molarity is equal to the number of moles present in liter of solution. Therefore, calculate number of moles as follows.

Molarity =
`\frac{\text{no. of moles}}{volume}`

0.15 M =
`\frac{\text{no. of moles}}{0.25 l}`

No. of moles = 0.0375 mol

Thus, we can conclude that moles present in given solution are 0.0375.