Question

A ball is projected vertically downward at a speed of 4.00 m/s. How far does the bal travel in 1.80 s? What is the velocity of the ball at that time?

Answer 1

1) Distance traveled equals 23.1 meters.

2) Final velocity equals 21.658 m/s.

Step-by-step explanation:

The problem can be solved using second equation of kinematics as

`s=ut+(1)/(2)at^(2)`

where

s is the distance covered

u is the initial speed of the ball

a is the acceleration the ball is under

t is time of travel

Applying the given values in the above equation we get

`s=4.0* 1.8+(1)/(2)* 9.81* 1.8^(2)\\\\s=23.1meters`

Part 2)

The velocity after 't' time can be obtained using first equation of kinematics.

`v=u+at`

Applying the given values we get

`v=4+9.81* 1.80\\\\\therefore v=21.658m/s`