Question

What is the net charge of a metal ball if there are 21,749 extra electrons in it?

Answer 1

`Q=3.47* 10^(-15)\ C`

Step-by-step explanation:

Given that,

Number of extra electrons, n = 21749

We need to find the net charge on the metal ball. Let Q is the net charge.

We know that the charge on an electron is
`q=1.6* 10^(-19)\ C`

To find the net charge if there are n number of extra electrons is :

Q = n × q

`Q=21749* 1.6* 10^(-19)\ C`

`Q=3.47* 10^(-15)\ C`

So, the net charge on the metal ball is
`3.47* 10^(-15)\ C`. Hence, this is the required solution.