Question

A proton is accelerated down a uniform electric field of 450 N/C. Calculate the acceleration of this proton.

Answer 1

The acceleration of proton will be
`431.137* 10^8m/sec^2`

Step-by-step explanation:

We have given electric field E = 450 N/C

Charge on proton
`=1.6* 10^(-19)C`

Force on electron due to electric field is given by
`F=qE=1.6* 10^(-19)* 450=720* 10^(-19)N`

Mass of electron
`m=1.67* 10^(-27)kg`

Now according to second law of motion
`F=ma`

So
`720*10^(-19)=1.67* 10^(-27)a`

`a=431.137* 10^8m/sec^2`

So the acceleration of proton will be
`431.137* 10^8m/sec^2`