Answer: The moles of water produced are 1.54 moles.
Step-by-step explanation:
To calculate the number of moles, we use the equation:
![\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}](https://img.qammunity.org/2020/formulas/chemistry/high-school/gwh5prgbdt4s2p8o8xquycz897bwt6lvw1.png)
Given mass of ethane = 15.42 g
Molar mass of ethane = 30.07 g/mol
Putting values in above equation, we get:
![\text{Moles of ethane}=(15.42g)/(30.07g/mol)=0.513mol](https://img.qammunity.org/2020/formulas/chemistry/college/r5c6etkwiwhy7f5aswv9dsi2caoeu6u3qr.png)
The chemical equation for the combustion of ethane follows:
![2C_2H_6+5O_2\rightarrow 4CO2+6H_2O](https://img.qammunity.org/2020/formulas/chemistry/college/yl8gjid20wx22wfppxk7v6sdqq0cjcb3h4.png)
By Stoichiometry of the reaction:
2 moles of ethane produces 6 moles of water
So, 0.513 moles of ethane will produce =
of water
Hence, the moles of water produced are 1.54 moles.