Question

Convert 1 cal/(m^2 * sec * °C) into BTU/(ft^2 * hr * °F)

Its easy enough to convert the energy, time, and area units, but how am I suppose to convert the temp units?

Answer 1

`1\ \frac{\text{cal}}{m^2* sec* ^\circ C}=0.03926\frac{\text{BTU}}{ft^2* hr* ^\circ F}`

Explanation:

To find : Convert
`1\ \frac{\text{cal}}{m^2* sec* ^\circ C}` into
`\frac{\text{BTU}}{ft^2* hr* ^\circ F}`

Solution :

We convert units one by one,

`1\text{ m}^2=10.7639\text{ ft}^2`

`1\text{ sec}=(1)/(3600)\text{ hour}`

`1\text{ cal}=0.003968\text{ BTU}`

Converting temperature unit,

`^\circ C* (9)/(5)+32=^\circ F`

`1^\circ C* (9)/(5)+32=33.8^\circ F`

So,
`1^\circ C=33.8^\circ F`

Substitute all the values in the unit conversion,

`1\ \frac{\text{cal}}{m^2* sec* ^\circ C}=(0.003968)/(10.7639* (1)/(3600)* 33.8)\frac{\text{BTU}}{ft^2* hr* ^\circ F}`

`1\ \frac{\text{cal}}{m^2* sec* ^\circ C}=(0.003968)/(0.101061)\frac{\text{BTU}}{ft^2* hr* ^\circ F}`

`1\ \frac{\text{cal}}{m^2* sec* ^\circ C}=0.03926\frac{\text{BTU}}{ft^2* hr* ^\circ F}`

Therefore, The conversion of unit is
`1\ \frac{\text{cal}}{m^2* sec* ^\circ C}=0.03926\frac{\text{BTU}}{ft^2* hr* ^\circ F}`