Question

Two rockets are flying in the same direction and are side by side at the instant their retrorockets fire. Rocket A has an initial velocity of +5300 m/s, while rocket B has an initial velocity of +8700 m/s. After a time t both rockets are again side by side, the displacement of each being zero. The acceleration of rocket A is -11 m/s^2. What is the acceleration of rocket B?

Answer 1

Answer:
`-18.05 m/s^2`

Step-by-step explanation:

Given

Initial velocity of rocket A (
`v_A`) 5300m/s

Initial velocity of rocket B(
`v_B`) 8700 m/s

after time t they have displacement=0

`s_A=5300* t+(1)/(2)* \left ( -11\right )t^2`

`0=5300* t+(1)/(2)* \left ( -11\right )t^2`

`t=(5300* 2)/(11)=963.63 s`

for Rocket B

`s_B=8700* t+(1)/(2)* \left ( a_B\right )t^2`

time is same for A & B

`0=8700* 963.63+(1)/(2)* \left ( a_B\right )963.63^2`

`a_B=(2* 8700)/(963.63)=-18.05 m/s^2`