Question

The driver of a sports car traveling at 10.0⁣m/s steps down hard on the accelerator for 5.0⁣s and the velocity increases to 30.0⁣m/s. What was the average acceleration of the car during the 5.0s time interval?

Answer 1

`a=4m/s^(2)`

Step-by-step explanation:

From the concept of average acceleration we know that

`a=(v_(2)-v_(1) )/(t_(2)-t_(1)  )`

From the exercise we know that

`v_(2)=30m/s\\v_(1)=10m/s\\t_(2)=5s\\t_(1)=0s`

So, the average acceleration of the car is:

`a=(30m/s-10m/s)/(5s)=4m/s^(2)`