Question

A brick is thrown upward from the top of a building at an angle of 25.7° above the horizontal and with an initial speed of 15.1 m/s. The acceleration of gravity is 9.8 m/s^2 If the brick is in flight for 3.4 s, how tall is the building? Answer in units of m

Answer 1

the building is 34.408 m tall

Step-by-step explanation:

given,

initial velocity of brick = 15.1 m/s

at an angle of = 25.7°

vertical component of the velocity

Vy = 15.1 sin 25.7°

= 6.54 m/s

we know

`s = u t + (1)/(2) a t^2`

`s = 6.54* 3.4 + (1)/(2)* -9.8 * 3.4^2`

s = -34.408 m

hence, the building is 34.408 m tall .