Question

A car travels in a straight line from a position 50 m to your right to a position 210 m to your right in 5 sec. a. What is the average velocity of the car?b. Construct a position vs. time graph and calculate the slope of the line of best fit.

Answer 1

The average velocity of the car is 32 m/s.

Step-by-step explanation:

Given that,

Initial position = 50 m

Final position = 210 m

Time = 5 sec

(a). We need to calculate the average velocity of the car

Using formula of average velocity

`v_(avg)=(v_(f)-v_(i))/(t)`

Put the value into the formula

`v_(avg)=(210-50)/(5)`

`v_(avg)=32\ m/s`

(b). We need to draw the position vs. time graph

We need to calculate the slope of the line of best fit.

Using formula of slop

`slope =(y_(2)-y_(1))/(x_(2)-x_(1))`

Put the value into the formula

`slope =(210-50)/(5-0)`

`slope =32`

Hence, The average velocity of the car is 32 m/s.