Question

How many milliequivalents of sodium chloride are contained with 3 L of normal saline?

Answer 1

466mEq

Explanation:

First, we need to know the concentration of NaCl in a normal saline solution, this is by definition 0.9%, meaning we have 0.9g of NaCl per 100ml of solution, we want to know how much NaCl we have in 3L (3000ml):

`3000ml*(0.9g)/(100ml)=27g=27000mg`

So, we have 27000mg in 3L of normal saline solution.

Now, acording to our milliequivalent (mEq) equation (
`mEq=(mg)/(pE)`) where pE is de molecular mass of NaCl divided by their charges, in this case 1:

`pE= (23+35)/(1)=(58)/(1) = 58`

Finally we substitute in the mEq formula:

`mEq=(mg)/(pE)=(27000)/(58)=466mEq`

I hope you find this information useful! Good luck!