Answer:
a) 6561
b) 3024
c) 1296
Explanation:
Given : Using the digits 1 through 9.
To find : The number of different 4-digit numbers such that :
(a) Digits can be used more than once.
(b) Digits cannot be repeated. 2 .
(c) Digits cannot be repeated and must be written in increasing order.
Solution :
Digits are 1,2,3,4,5,6,7,8,9
We have to form different 4-digit number let it be _ _ _ _
(a) Digits can be used more than once.
For first place there are 9 possibilities.
For second place there are 9 possibility as number repeats.
Same for third and fourth we have 9 possibility.
The number of ways are
![9* 9* 9* 9=6561](https://img.qammunity.org/2020/formulas/mathematics/college/xns4fyso2mhewksh0m6rwyjee78gz8pcvt.png)
(b) Digits cannot be repeated.
For first place there are 9 possibilities.
For second place there are 8 possibility as number do not repeats.
For third place there are 7 possibility as number do not repeats.
For fourth place there are 6 possibility as number do not repeats.
The number of ways are
![9* 8* 7* 6=3024](https://img.qammunity.org/2020/formulas/mathematics/college/ceb7hbl9xf4ojwkeu3u762btk2m2qj6pib.png)
c) Digits cannot be repeated and must be written in increasing order.
The number which we can use on first position are 1,2,3,4,5,6 i.e. 6
The number which we can use on second position are 2,3,4,5,6,7 i.e. 6
The number which we can use on third position are 3,4,5,6,7,8 i.e. 6
The number which we can use on fourth position are 4,5,6,7,8,9 i.e. 6
Total number of ways are
![6* 6* 6* 6=1296](https://img.qammunity.org/2020/formulas/mathematics/college/o9k30gsehyyqly7s38p6i6jadorbbedkjh.png)